(x^2+5/x)+2=5(x+1)/x

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Solution for (x^2+5/x)+2=5(x+1)/x equation:


D( x )

x = 0

x = 0

x = 0

x in (-oo:0) U (0:+oo)

x^2+5/x+2 = (5*(x+1))/x // - (5*(x+1))/x

x^2-((5*(x+1))/x)+5/x+2 = 0

x^2-5*x^-1*(x+1)+5/x+2 = 0

(-5*x^-1*x*(x+1))/x+(x*x^2)/x+5/x+(2*x)/x = 0

x*x^2-5*x^-1*x*(x+1)+2*x+5 = 0

x^3-5*x+2*x-5+5 = 0

x^3-5*x+2*x = 0

x^3-3*x = 0

x^3-3*x = 0

x*(x^2-3) = 0

1*x^2 = 3 // : 1

x^2 = 3

x^2 = 3 // ^ 1/2

abs(x) = 3^(1/2)

x = 3^(1/2) or x = -3^(1/2)

x*(x-3^(1/2))*(x+3^(1/2)) = 0

(x*(x-3^(1/2))*(x+3^(1/2)))/x = 0

(x*(x-3^(1/2))*(x+3^(1/2)))/x = 0 // * x

x*(x-3^(1/2))*(x+3^(1/2)) = 0

( x+3^(1/2) )

x+3^(1/2) = 0 // - 3^(1/2)

x = -3^(1/2)

( x-3^(1/2) )

x-3^(1/2) = 0 // + 3^(1/2)

x = 3^(1/2)

( x )

x = 0

x in { 0}

x in { -3^(1/2), 3^(1/2) }

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